WAP to count the number of digits in a number in Java
Logical Steps:
- Take one number and set a counter variable to 0 to keep track of the number of digits.
-
Use a loop:
- Divide the number by 10 in each iteration.
- Increment the counter until the number becomes 0.
- Print the counter as the digit count.
Programs:
-
Below is the simple program:
public class DigitCounter { public static void main(String[] args) { int no = 1382; int count = 0; while (no != 0) { no = no / 10; count++; } System.out.println("The number of digits is: " + count); } }Output:
The number of digits is: 4
-
Below is the program by taking user input:
import java.util.Scanner; public class DigitCounter { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.print("Enter a number: "); int no = scanner.nextInt(); int count = 0; while (no != 0) { no = no / 10; count++; } System.out.println("The number of digits is: " + count); scanner.close(); } }Output:
Enter a number: 72513 The number of digits is: 5
Program Explanation
-
Take input from the user using
Scannerand store it in an integer variableno. -
Initialize a counter
count = 0. This variable will track the number of digits. -
Use a while loop to iterate until
nobecomes 0.-
In each iteration, divide
noby 10 (no = no/10;) to remove the last digit. -
Increment
countby 1 (count++) to record that a digit has been counted.
-
In each iteration, divide
-
When the loop ends, the
countvariable will hold the total number of digits in the input number. -
Display the result using
System.out.println("The number of digits is: " + count);.
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